<p>A sample of peanut oil weighing 1.5763g is added to 25 mL of 0.4210 M KOH after saponification is complete 8.46 mL of 0.2732 M&nbsp;<math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>H</mi><mn>2</mn></msub><mi>S</mi><msub><mi>O</mi><mn>4</mn></msub></math>&nbsp;is needed to neutralise excess KOH. The saponification number of peanut oil is:</p>