<p>In a series LR circuit&nbsp;<span class="equation">\(X_{L}\)</span>&nbsp;= R and power actor of the circuit is&nbsp;<span class="equation">\(P_{1}\)</span>. When capacitor with capacitance C such that&nbsp;<span class="equation">\(X_{L} = X_{C}\)</span>&nbsp;is put in series, the pOwer factor becomes <span class="equation">\(P_{2}\)</span>&nbsp;Calculate <span class="equation">\(P_{1} /P_{2}\)</span>​​​​​​​​​​​​​​​​​​​​​</p>