<p>A body of mass &#39;m&#39; is projected with a speed &#39;u&#39; making an angle of&nbsp;<span class="equation">\(45^0\)</span>&nbsp;with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as&nbsp;<span class="equation">\(\frac{\sqrt{2}mu^3}{Xg}\)</span>​​​​​​​. The value of &#39;X&#39; is______</p>