<p>A square shaped hole of side I =&nbsp;<span class="equation">\(\frac{a}{2}\)</span>&nbsp;&nbsp;is carved out at a distance d =&nbsp;<span class="equation">\(\frac{a}{2}\)</span>&nbsp;from the centre &lsquo;O&rsquo; of a uniform circular disk of radius a. If the distance of the centre of mass of the remaining portion form O is&nbsp;<span class="equation">\(-\frac{a}{X}\)</span>, value of X (to the nearest integer) is :</p>

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